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 Problem Statement for SubtreeSumHash

Problem Statement

    You are given a tree T with n nodes. The nodes are numbered 0 through n-1. Each node of the tree has a positive integer weight. You are given the weights in the int[] weight with n elements. You are also given a int[] p with n-1 elements that describes the edges of the tree: for each valid i, there is an undirected edge between nodes (i+1) and p[i]. The constraints ensure that this will produce a valid tree.

A subtree of T is any subgraph of T that is a tree. The weight of a subtree is the sum of the weights of its vertices. Let S be the multiset that contains the weights of all nonempty subtrees of T. (In other words, for each subtree of T we calculate its total weight and add the result to S. Note that S may contain some duplicates.)

You are also given an int x. This value is used to define the hash of the multiset S: Hash(S) is defined as the sum of x^s over all elements s of S. For example, if S = {2, 3, 3} then Hash(S) = x^2 + x^3 + x^3.

Please calculate and return the value Hash(S) modulo 1,000,000,007.


Parameters:int[], int[], int
Method signature:int count(int[] weight, int[] p, int x)
(be sure your method is public)


-weight will contain between 1 and 50 elements, inclusive.
-Each element in weight will be between 1 and 1,000,000,000, inclusive.
-p will contain exactly |weight|-1 elements.
-For each i, 0 <= p[i] <= i.
-x will be between 1 and 1,000,000,000, inclusive.


Returns: 1102110
The tree contains the edges 1-0 and 2-1, so it looks like this: 0 - 1 - 2.

This tree has 6 subtrees: {0}, {1}, {2}, {0,1}, {1,2}, and {0,1,2}. Their weights are 1, 2, 3, 3, 5, and 6, respectively. Hence, S = {1, 2, 3, 3, 5, 6} and Hash(S) = x^1 + x^2 + 2*x^3 + x^5 + x^6 = 10 + 100 + 2*1000 + 100000 + 1000000 = 1102110.
Returns: 11
There are 11 subtrees. Their weights do not matter: as x = 1, Hash(S) is simply the number of subtrees.
Returns: 999999937
The answer is 10^10 % (10^9+7).
Returns: 46327623

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This problem was used for:
       2017 TCO Algorithm Round 1B - Division I, Level Three