Problem Statement   Given is a positive integer W.
We will use W to define a function f.
The value f(x) is computed as follows:
 If x is not a positive integer, f(x) is undefined.
 Let y = x modulo W. If y is zero, f(x) is undefined.
 Otherwise, f(x) = x/y (where "/" denotes exact real division).
For any positive integer x, consider the following infinite sequence:
x, f(x), f(f(x)), f(f(f(x))), and so on.
We say that f is always defined for x if all the terms of the above sequence are defined.
(In other words, there is no positive integer k such that f^k(x) is undefined.
Here, f^k denotes f applied k times.)
You are given longs L and R, and the int W used in our function f.
Count all x between L and R, inclusive, such that f is always defined for x.
Return that count.
  Definition   Class:  AlwaysDefined  Method:  countIntegers  Parameters:  long, long, int  Returns:  long  Method signature:  long countIntegers(long L, long R, int W)  (be sure your method is public) 
    Constraints    L will be between 1 and 10^18, inclusive.    R will be between L and 10^18, inclusive.    W will be between 2 and 3000, inclusive.   Examples  0)     Returns: 1  For W = 4, we have f(10) = 5, f(f(10)) = 5, f(f(f(10))) = 5 and so on, thus f is always defined for x = 10. 

 1)     Returns: 50  For W = 2, f is always defined for odd integers but not for even integers. There are 50 odd integers between 1 and 99, inclusive. 

 2)     3)    
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