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   Problem Statement  

 Problem Statement for FoxAndWord

Problem Statement

    One day, Fox Ciel looked at the words "tokyo" and "kyoto" and noticed an unusual property: We can split "tokyo" into "to"+"kyo", and then swap those two parts to obtain "kyo"+"to" = "kyoto".



Formally, let S and T be two different strings. We call the pair (S,T) interesting if there are two non-empty strings A and B such that S = A+B and T = B+A. For example, according to this definition, if S="tokyo" and T="kyoto", then the pair (S,T) is interesting, because we can find A="to" and B="kyo".



You are given a String[] words. Return the number of interesting pairs we can find among the elements of words. Only count each pair once. E.g., ("tokyo","kyoto") and ("kyoto","tokyo") is the same interesting pair.
 

Definition

    
Class:FoxAndWord
Method:howManyPairs
Parameters:String[]
Returns:int
Method signature:int howManyPairs(String[] words)
(be sure your method is public)
    
 

Constraints

-words will contain between 2 and 50 elements, inclusive.
-Each element of words will contain between 1 and 50 characters, inclusive.
-Each character in each element of words will be a lowercase letter ('a'-'z').
-All the elements in words will be pairwise distinct.
 

Examples

0)
    
{"tokyo", "kyoto"}
Returns: 1
As mentioned in the problem statement, ("tokyo", "kyoto") is an interesting pair.
1)
    
{"aaaaa", "bbbbb"}
Returns: 0
("aaaaa", "bbbbb") is not an interesting pair.
2)
    
{"ababab","bababa","aaabbb"}
Returns: 1
There is one interesting pair: ("ababab","bababa"). Note that for this interesting pair there is more than one way to choose the strings A and B.
3)
    
{"eel", "ele", "lee"}
Returns: 3
4)
    
{"aaa", "aab", "aba", "abb", "baa", "bab", "bba", "bbb"}
Returns: 6
5)
    
{"top","coder"}
Returns: 0
Different elements of words may have different lengths.

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This problem was used for:
       Single Round Match 604 Round 1 - Division II, Level One