JOIN

 Problem Statement

Problem Statement for STable

Problem Statement

You are given two Strings s and t. All characters of s and t are distinct. No character of s is present in t and no character of t is present in s.

Let N be the length of s, and M be the length of t. Define a 2-dimensional string array "table" as follows:

• table[i][0] = s[i-1] (1<=i<=N)
• table[0][j] = t[j-1] (1<=j<=M)
• table[i][j] = min(table[i-1][j], table[i][j-1]) + max(table[i-1][j], table[i][j-1]) (1<=i<=N, 1<=j<=M)

Note that min and max are defined by the lexicographical order of strings (see Notes for a more formal definition), and A+B means the concatenation of strings A and B.

Your task is to find a substring of table[N][M]. Let L be the length of table[N][M]. Return the substring of table[N][M] whose start position (0-indexed) is pos and length is min(50, L-pos).

Definition

 Class: STable Method: getString Parameters: String, String, long Returns: String Method signature: String getString(String s, String t, long pos) (be sure your method is public)

Notes

-A string X is defined as smaller than a string Y if and only if X is a prefix of Y or X has a smaller character than Y at the first position where they differ.
-The order of characters is defined by their ASCII codes: '0'<...<'9'<'A'<...<'Z'<'a'<...<'z'.

Constraints

-s and t will each contain between 1 and 30 characters, inclusive.
-All characters of s and t will be distinct.
-No character of s will be present in t.
-No character of t will be present in s.
-s and t will contain only letters ('A'-'Z', 'a'-'z') and digits ('0'-'9').
-pos will be between 0 and L-1, inclusive, where L is the length of table[N][M] as defined in the statement.

Examples

0)

 `"ad"` `"cb"` `0`
`Returns: "acbacd"`
 In this case, the array "table" is as follows. ```----------------- | | c | b | ----------------- |a| ac | acb | ----------------- |d| acd |acbacd| ----------------- ```
1)

 `"fox"` `"cat"` `0`
`Returns: "acfcfoacftacfcfocfox"`
2)

 `"Ra6b1t"` `"W0lf"` `66`
`Returns: "RWab0RWRWa0RWl0RWRWa6RWa0RWRWa6RWa6RWab0RWRWa6RWa6"`
 In this case, return 50 characters.
3)

 `"M0HAXG"` `"COFU12"` `919`
`Returns: "MOFU2"`
4)

 `"a0B1c2D3e4F5gHiJkLmN"` `"A9b8C7d6EfGhIjKlMn"` `9876543210`
`Returns: "B10AaB1c0Aa9Aa0AaB0AaB10AaB1c0AaB1c20Aa9Aa0AaB0Aa9"`
5)

 `"TCOR2"` `"MEDiUm"` `350`
`Returns: "MTDEMTiCMTEMTDEMTDEMTiDEMTiUCMTEMTCMTOCMTEMTDEMTCM"`

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This problem was used for:
2011 TCO Algorithm Online Round 2 - Division I, Level Two